A body is slipping from an inclined plane of height h and length l . If the angle of inclination is `theta` , the time taken by the body to come from the top to the bottom of this inclined plane is

Options

A. `sqrt((2h)/(g))`
B. `sqrt((2l)/(g))`
C. `(1)/(sin theta)sqrt((2h)/(g))`
D. `sin theta sqrt((2h)/(g))`

Answer

C

Explanation

`because (h)/(l)=sin theta rArr l=(h)/(sin theta)`
component of g along l is g `sin theta`
`t=sqrt((2l)/(a))=sqrt((2h)/(sintheta/(g sin theta)))=(1)/(sin theta)sqrt((2h)/(g))`