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What is the ratio of P.E. w.r.t. ground ...

What is the ratio of P.E. w.r.t. ground and K.E. at the top most point of the projectile motion:-

A

`cos^(2)theta`

B

`sin^(2)theta`

C

`tan^(2)theta`

D

`cot^(2)theta`

Text Solution

Verified by Experts

The correct Answer is:
C
`(K.E.)_("TOP")=(1)/(2)mu^(2)cos^(2)theta`
vertical part of initial `K.E.=(P.E.)_("top")`
`(P.E)_("TOP")=mgH=mg(u^(2)sin^(2)sin^(2)theta)/(2g)=(1)/(2)mu^(2) sin^(2)theta`
`rArr((P.E.)_("TOP"))/((K.E.)_("TOP"))=`
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