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The velocity of projection of oblique pr...

The velocity of projection of oblique projectile is `(6hati+8hatj)ms^(-1)` The horizontal range of the projectile is

A

4.8 metre

B

9.6 metre

C

19.2 metre

D

14.0 metre

Text Solution

Verified by Experts

The correct Answer is:
B
`vev=6hati+8hatj`
`rArr u cos theta=6` and `u sin theta=8`
`R=(2(u sin theta)(u cos theta))/(g)=(2xx6xx8)/(10)=(48)/(5)`
R=9.6m
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