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The maximum range of a projecitle fired ...

The maximum range of a projecitle fired with some initial velocity is found to be 1000 metre The maximum height (H) reached by this projectile is:-

A

250 metre

B

500 metre

C

1000metre

D

2000metre

Text Solution

Verified by Experts

The correct Answer is:
A

`R=(u^(2)sin 2 theta)/(g)` At `theta=45^(@)`
`R_("max")=(u^(2))/(g)=1000rArr u=100 m//s`
`rArr h=(u^(2)sin^(2)45^(@))/(2g)=(10000)/(2xx10xx2)=250m`
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Knowledge Check

  • The maximum range of projectile fired with some initial velocity is found to be 1000 m, in the absence of wind and air resisstance. The maximum height reached by the projectile is

    A
    250 m
    B
    500 m
    C
    1000 m
    D
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    `(3u^(2))/(5g)`
    C
    `(4u^(2))/(5g)`
    D
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    `v_(A) gt v_(B) gt v_(C)`
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