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In a transformer ratio of secondary turn...

In a transformer ratio of secondary turns `(N_(2))` and primary turns `(N_(1))`,i.e. `N_(2)/N_(1)=4`.if the voltage applied in primary is `200 V,50 Hz`, find (a)voltage inducted in secondary (b)If current in primary is `1A`, find the current in secondary if the transformer is (i)Ideal and (ii)`80%` efficient and there is no flux leakage.

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The correct Answer is:
(a)`800 V` , (b)(i)`0.25 A` ,(ii)`0.2 A`.

(a)`V_(2)/V_(1)=N_(2)/N_(1)=4 , rArrV_(2)=200xx4=800`
(b)(i)`I_(2)/I_(1)=N_(2)/N_(1)=1/4 rArr i_(2)=1/4=0.25 A`
(ii)`I_(1)V_(1)xx0.80=V_(2)I_(2) rArr I_(2)=0.8xx0.25=0.2 A`
(a)`V_(2)/V_(1)=N_(2)/N_(1)=4 , rArrV_(2)=200xx4=800`
(b)(i)`I_(2)/I_(1)=N_(2)/N_(1)=1/4 rArr i_(2)=1/4=0.25 A`
(ii)`I_(1)V_(1)xx0.80=V_(2)I_(2) rArr I_(2)=0.8xx0.25=0.2 A`
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