r.m.s. value of current `i=3+4 sin (omega t+pi//3)` is:

Options

A. `5 A`
B. `sqrt17 A`
C. `5/sqrt2 A`
D. `7/sqrt2 A`

Answer

B

Explanation

`I_(rms)=[(underset(0)overset(T)inti^(2)dt)/T]^(1/2)=[underset(0)overset(T)int[(3+4sin(omegat+pi//3))]^(2)/Tdt]^(1//2)=sqrt17`