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A sinusoidal ac current flows through a ...

A sinusoidal ac current flows through a resistor of resistance R . If the peak current is `I_(p)` , then the power dissipated is

A

`I_(1)^(p)R cos theta`

B

`1/2I_(p)^(2)R`

C

`4/pi I_(p)^(2)R`

D

`1/pi^(2)I_(p)^(2)R`

Text Solution

Verified by Experts

The correct Answer is:
B
`ltP gt = I_(rms)^(2) R=(I_(p)/sqrt2)^(2) R=(I_(p)^(2)R)/2`
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