Assuming all the surfaces to be smoth, if the time period of motion of the ball is `N xx 10^(-1) sec ` then find `N`. Neglect the small effect of bend near the bottom. `(g = 10m//s^(2))`

Answer

16

Explanation

`S = (h)/(sin30), a = g sin 30, h = 20 cm , u = 0`
`S = ut + (1)/(2) at^(2)`
`rArr t = sqrt((2S)/(a)) = sqrt((2 xx (0.2 xx 2))/(10 xx (0.5))) = 0.4`
For `BC` max height reached by the particle will be same as `h = 20 cm`
(by energy conservation)
and for `BA` and `BC , t = 0.4`
Total time period `= 0.4 xx 4 = 1.6` second `= 16 xx 10^(-1) sec`
`:. N = 16`