Calculate the number of `KJ` necessary to raise the temperature of `60.0 gm` of aluminium from `35^(@)` to `55^(@)C`. Molar heat capcacity of `Al` is `24 J mol^(-1)K^(-1)`
Text Solution
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`q = nC Delta T = ((60)/(27)) xx 24 xx (55-35) = 1066 J = 1.066 kJ`
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