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A piece of zinc at a temperature of 20^(...

A piece of zinc at a temperature of `20^(@)C` weighing `65.38 g` is dropped into `180 g` of boiling water `(T=100^(@)C)` The specific heat of zince is `0.4 J g^(-1)C^(-1)` and that of water is `4.2J g^(-1^(@))C^(-1)`. What is the final common temperature reached by both the zinc and water ?

A

`97.3^(@)C`

B

`33.4^(@)C`

C

`80.1^(@)C`

D

`60.0^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A

Let final common temperature is `T_(f)`
Heat gained by Zinc piece`=` Heat lost by water
`0.4 (T_(f)-20)xx65.38=4.2(100-T_(f))xx180 rArrT_(f)=97.3^(@)C`
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