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4 KJ of heat is absorbed when 1 mole of ...

`4 KJ` of heat is absorbed when `1` mole of ice melts at `0^(@)C` and at constant pressure `1 atm`. If molar volume of ice and water are `19 ml` and `18 ml` respectively, then
[Take `1 atm=10^(5)Pa`]

A

`Delta H gt Delta U`

B

`Delta U gt Delta H`

C

`Delta U =4.1 KJ`

D

`Delta U= 4.0001 KJ`

Text Solution

Verified by Experts

The correct Answer is:
B, D
`Delta H= 4KJ`
`Delta H=Delta U+Delta(PV)`
`Delta U= 4-P(V_(2)-V_(1))=4-(10^(5)(18-19)xx10^(-6))/(10^(3))= 4+1xx10^(-4)=4.0001 KJ`
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