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One mole of an ideal monoatomic gas at t...

One mole of an ideal monoatomic gas at temperature `T` and volume `1L` expands to `2L` against a constant external pressure of one atm under adiabatic conditions, then final temperature of gas will be:

A

`T+(2)/(3xx0.0821)`

B

`T-(2)/(3xx0.0821)`

C

`(T)/(2^(5//3-1))`

D

`(T)/(2^(5//3+1))`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta U=W`
`nCV(T_(2)-T)= -Pxx(V_(2)-V_(1))`
`(3)/(2)R(T_(2)-T)= -1 " " :. T_(2)=T-(2)/(3xx0.0821)`
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