Home
Class 12
CHEMISTRY
The ratio of P to V at any instant is co...

The ratio of `P` to `V` at any instant is constant and is equal to `1`, for a monoatomic ideal gas under going a process. What is the molar heat capacity of the gas

A

`(3R)/(2)`

B

`(4R)/(2)`

C

`(5R)/(2)`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
From first law of thermodynamics, `Delta E=q+w rArr nC_(v)dT=nCdT'=PdV`…..(1)
Now according to process, `P=V` and according to ideal gas equation, `PV=nRT`
We have, `V^(2)=nRT`
On differentiating, `2VdV=nRdT` and `PdV=VdV=(nRdT)/(2)`
So, from list equation we have, `nC_(v)dT=nCdT-(nRdT)/(2)`
So, `C_(v)=C-(R )/(2)` Hence, `C=(4R)/(2)`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE|Exercise Main|5 Videos

  • THERMODYNAMICS

    RESONANCE|Exercise Exercise-1 Part-I Subjective question|30 Videos

  • THERMODYNAMICS

    RESONANCE|Exercise Exercise-2 part -IV : Comprehension|11 Videos

  • TEST SERIES

    RESONANCE|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

The ratio of P to V at any instant is constant and is equal to 1. for a monoatomic ideal gas undergoing a process. What is the molar heat capacity of the gas?

The molar heat capacity for an ideal gas

A monoatomic ideal gas undergoes a process ABC . The heat given to the gas is

The molar heat capacity of a gas in a process

The molar heat capacity for an ideal gas cannot

A monotomic ideal gas undergoes a process in which the ratio of p to V at any instant is constant and equals to 1. what is the molar heat capacity of the gas?

The molar heat capacity for a gas at constant T and P is

Find the molar heat capacity (in terms of R ) of a monoatomic ideal gas undergoing the process: PV^(1//2) = constant ?