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Calculate the standard internal energy o...

Calculate the standard internal energy of formation of liquid methyl acetate `(CH_(3)COOCH_(3))` from its standard enthalpy of foramtion, which is `-44.291 kJ "mole"^(-1)` at `25^(@)C`

A

`-433`

B

`+433`

C

`-452.82`

D

`452.82`

Text Solution

Verified by Experts

The correct Answer is:
A
`3C_((s))+3H_(2(g))+O_(2(g))rarrCH_(3)COOCH_(3)(l)DeltaH_(f)^(0)= -442.91`
`Delta U=DeltaH-Delta n_(g)RT`
`=(-442.91-(-4)xx8.314xx(298)/(1000))kJ "mole"^(-1)`
`= -433 kJ"mole"^(-1)`
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