If `S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1)`
`SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1)`
`SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1)`
`H_(2)+(1)/(2)O_(2)toH_(2)SO_(4),DeltaH=-287.3 " kJ" " mole"^(-1)`
the enthlapy of formation of `H_(2)SO_(4)` at 298 K will be

Options

A. `-814.4kJ mol^(-1)`
B. `+814.4 kJ"mole"^(-1)`
C. `-650.3 kJ"mole"^(-1)`
D. `-433.7 kJ "mole"^(-1)`

Answer

A

Explanation

`{:(S+O_(2)rarrSO_(2)" "DeltaH=-298.2KJ//"mole"" ....(1)"),(SO_(2)+(1)/(2)O_(2)rarrSO_(3)" "Delta H= -98.7 KJ//"mole" " ".... (2)),(SO_(3)+H_(2)OrarrH_(2)SO_(4)" "Delta H= -130.2 KJ//"mole"" "....(3)),(H_(2)+(1)/(2)O_(2)rarrH_(2)O " "Delta H= -287.3 KJ//"mole"" .....(4)"),(bar("Adding"(1),(2),(3) and (4) "we get desired equation.")):}`