Home
Class 12
CHEMISTRY
The standard enthalpy of formation (Delt...

The standard enthalpy of formation (`DeltaH_(f)^(@))` at `398` K fir methane , `CH_(4(g))` is `748 KJ mol^(-1)`. The additional information required to determine the average energy for `C-H` bond formation would be :

A

the dissociation energy of `H_(2)` and enthalpy fo sublimation of carbon

B

latent heat of vapourisation of methane

C

the first four ionization energies of carbon and electron gain enthalpy of hydrogen

D

the dissociation energy of hydrogen molecule , `H_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`C=2H_(2) rarr CH_(4), DeltaH^(@) = -74.8 KJ mol^(-1)`
In order to calculate average energy for C-H bond formation we should know the following data. `C("graphite") rarr C(g), DeltaH, `=enthalpy of sublimation of carbon
`H_(2)(g) rarr 2H(g) , DeltaH^(@)` bond dissociation energy of `H_(2)`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part-3 :(Subjective questions)|6 Videos
  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part-3 :(Subjective questions)Section A|1 Videos
  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part-1 :(previous years)|8 Videos
  • TEST SERIES

    RESONANCE|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

The standard enthalpy of formation (Delta_(f)H^(@)) at 298K for methane (CH_(4(g))) is -74.8kJ mol^(-1) . The additional information required to determine the average energy for C-H bond formation would be :

The standard enthalpy of formation of NH_(3) is -46.0KJ mol^(-1) . If the enthalpy of formation of H_(2) from its atoms is -436KJ mol^(-1) and that of N_(2) is -712KJ mol^(-1) , the average bond enthalpy of N-H bond in NH_(3) is

The standard enthalpy of formation of NH_(3) is -46.0 kJ mol^(-1) . If the enthalpy of formation of H_(2) from its atoms is -436 kJ mol^(-1) and that of N_(2) is -7112kJ mol^(-1) , the average bond enthalpy of N-H bond in NH_(3) is :-