Home
Class 12
CHEMISTRY
A gaseous reactant A forms two different...

A gaseous reactant A forms two different product, in parallel reaction , B and C as follows:
`A rarr B, DeltaH^(@) =-3KJ, DeltaS^(@) = 20JK^(-1)" , " "A rarr C, DeltaH^(@) =-3.6KJ, DeltaS^(@) = 10 JK^(-1)`
Discuss the relative stability of B and C on the basis of Gibb's free energy change at `27^(@)C.`

Text Solution

Verified by Experts

The correct Answer is:
`DeltaG^(@)` indicates that B is more stable than C.

`A rarr B" "DeltaH^(@) =-3KJ " "DeltaS^(@)=20 J//KJ`
`A rarr C " "DeltaH^(@) =- 3.6 KJ " "DeltaS^(@)=10J//KJ`
`(i)` For `A rarr B , " " DeltaG = DeltaH -TDeltaS =- 3 -(300xx20)/(1000) =-9KJ =- 9000 J`
`(ii)` For `A rarr C , " " DeltaG =- 3.6-(300xx10)/(1000) =- 6.6 KJ =- 6600 J `
`DeltaG_(@) `Indicate that B is more stable than C.
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part-3 :(Only one option correct type) section A|8 Videos
  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part-3 :(Only one option correct type) section B|12 Videos
  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part-3 :(Subjective questions)Section B|8 Videos
  • TEST SERIES

    RESONANCE|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

A+B rarr C, DeltaH = +60 kJ/mol E_(a_f) is 150 kJ. What is the activation energy for the backward reaction ?

For the reaction at 300K (take R=8JK^-1mole^-1 2A(g)+B(s)rarr2D(g) , Delta U^(0)=-10kJ and Delta S^(0)=-50JK^-1 . Find the value of Delta G^(0)

For the reaction, 2A (s) + 2B (g)to C (g) + D(s) at 298K Delta U ^(@) =-10.5KJ and Delta S ^(@)=-44.10 JK^(-1) Calculate Delta G ^(@) for the reaction (in Joules).

For a gaseous reaction A+3BhArr 2C,DeltaH^(@)=-90.0kJ, DeltaS^(@)=-200.0jk^(-1) AT 400k. The DeltaG^(@) for the reaction (1)/(2)A+(3)/(2)B rarr C at 400K is :

For a reaction A rarr B, E_(a) = 10 kJ mol^(-1), DeltaH = 5 kJ mol^(-1) . Thus, potential energy profile for this reaction is: