Home
Class 12
CHEMISTRY
Dependence of Spontaneity on Temperature...

Dependence of Spontaneity on Temperature:
For a process to be spontaneous , at constant temperature and pressure , there must be decrease in free energy of the system in the direction of the process , i.e. `DeltaG_(P.T) lt 0. DeltaG_(P.T) =0` implies the equilibrium condition and `DeltaG_(P.T) gt 0` corresponds to non- spontaneity.
Gibbs- Helmholtz equation relates the free energy change to the enthalpy and entropy changes of the process as : `" "DeltaG_(P.T) = DeltaH-TDeltaS" ""..."(1)`
The magnitude of `DeltaH` does not change much with the change in temperature but the entropy factor `TDeltaS` change appreciably . Thus, spontaneity of a process depends very much on temperature.
For endothermic process, both `DeltaH` and `DeltaS` are positive . The energy factor, the first factor of equation, opposes the spontaneity whereas entorpy factor favours it. At low temperature the favourable factor `TDeltaS` will be small and may be less than `DeltaH, DeltaG` will have positive value indicated the nonspontaneity of the process. On raising temperature , the factor `TDeltaS` Increases appreciably and when it exceeds `DeltaH, DeltaG` would become negative and the process would be spontaneous .
For an expthermic process, both `DeltaH` and `DeltaS` would be negative . In this case the first factor of eq.1 favours the spontaneity whereas the second factor opposes it. At high temperature , when `T DeltaS gt DeltaH, DeltaG` will have positive value, showing thereby the non-spontaneity fo the process . However , on decreasing temperature , the factor ,`TDeltaS` decreases rapidly and when `TDeltaS lt DeltaH, DeltaG` becomes negative and the process occurs spontaneously. Thus , an exothermic process may be spontaneous at low temperature and non-spontaneous at high temperature.
For the reaction at `298 K ,2A + B rarr C`
`DeltaH =100 kcal` and `DeltaS=0.050 kcal K^(-1)`. If `DeltaH` and `DeltaS` are assumed to be constant over the temperature range, above what temperature will the reaction become spontaneous?

A

1000 K

B

1500 K

C

2000 K

D

2500 K

Text Solution

Verified by Experts

The correct Answer is:
C

Reaction to be spontaneous
`DeltaG lt 0 implies DeltaH-TDeltaS lt0 implies DeltaT gt (DeltaH)/(DeltaS) implies T gt (100xx10^(3))/(05xx10^(3)) implies T gt 2000` K.
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part:(I)|23 Videos
  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 part-1 Advanced level Solutions|30 Videos
  • THERMODYNAMICS

    RESONANCE|Exercise exercise-2 Part:(III): One or more than one options correct|10 Videos
  • TEST SERIES

    RESONANCE|Exercise CHEMISTRY|50 Videos