One mole of solid Zn is placed in excess of dilute `H_(2)SO_(4)` at `27^(@)C` in a cylinder fitted with a piston . Find the work done for the process of the area of piston is `500 cm^(2)` and it moves out by 50 cm against a pressure of 1 atm during the reaction.
`Zn(s) + 2H^(+)(aq) hArr Zn^(2+) (aq) + H_(2)(g)`

Options

A. `-1.53 KJ `
B. `-2.53 KJ`
C. Zero
D. 2.53 KJ

Answer

B

Explanation

`W=-P_("ext")(DeltaV)=- (1 atm) xx 500 xx50 xx 10^(-3)L=-25L atm =-25xx101.3 xx 10^(-3)KJ=- 2.53 KJ`