The enthy change for the reaction of 50 ml of ethylene with 50. 0 ml of ` H_(2)` at 1.5 atm pressure is `DeltaH =- 0.31 KJ `. What is the `DeltaU` ?

Options

A. `-0.3024`
B. `0.6048`
C. `0.1.2`
D. None

Answer

A

Explanation

`{:(C_(2)H_(4) ,"+", H_(2), rarr ,C_(2)H_(3)),(50ml, ,50ml,,o),(X,,X,,50ml):}`
`DeltaH=DeltaU+P(DeltaV)`
`-0.31=DeltaU + 1.5 xx 1.01 xx 10^(5) (-50 xx 10^(-6))`.
`DeltaU=- 0.3024 KJ .`