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Calculate the free energy change at 298 ...

Calculate the free energy change at 298 K for the reaction,
`Br_(2)(l)+ Cl_(2)(g) rarr 2BrCl(g)`. For the reaction `DeltaH^(@)=29.3` KJ & the entropies of `Br_(2)(l),Cl_(2)(g)` & `BrCl(g)` at the 298 K are 152.3,223.0,239.7 J `"mol^(-1)K^(-1)` respectively.

A

`-1721.8 J`

B

`-60321.8 J`

C

`+60321.8 J`

D

`+1721.8J`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG-29.3 xx10^(3)-(2xx239.7 - 152.3 -223)xx298 =-1721.8 "Joule".`
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