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One gram sample of oxygen undergoes free...

One gram sample of oxygen undergoes free expansion from 0.75L to 3.0 L at 298 K. Calculate `DeltaS`, q,w `DeltaH "and" DeltaE`

A

`DeltaS=0.36 JK^(-1)`

B

W=227.97 J

C

q=-227.97 J

D

`DeltaH=107.28 J`

Text Solution

Verified by Experts

The correct Answer is:
A
Since . Expansion occurred at constant temperature ,
`DeltaS=nR "In" (V_(2))/(V_(1)) =(1)/(32) xx 8.314 "In" (3.0)/(0.75)=0.36 JK^(-1)`
Since , this is case of free expansion , `P_("ext")=0 " " implies " "-W=P_("ext")DeltaV=0,q=0`
Also , since , `DeltaT=0 implies DeltaH=DeltaE=0.`
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