The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S `cm^(-1)` . Calculate its molar conductivity.

Explanation

Here conducitivity, `K=0.0248Scm^(-1)`
Molarity `M=0.20M`
Molar conductivity `^^_(m)=(1000xxk)/(M)=(1000xx0.0248)/(0.20)=124Scm^(2)mol^(-1)`