The electrical resistance of a column of `0.05 " mol " L^(-1)` NaOH solution of diameter 1 cm and length 50 cm is `5.55xx10^(3)" ohm "`.Calculate its resistivity,conductivity and molar conductivity.

Explanation

Cell constant `=(l)/(a)=(50cm)/(pir^(2))=(50cm)/((22)/(7)xx(1)/(2)xx(1)/(2))=(50cm)/(0.784cm^(2))`
`rho=(1)/(k)=Rxx(a)/(l)=(5.55xx10^(3)ohmxx0.785cm^(2))/(50cm)=87.135ohmcm`
`K=(1)/(rho)=(1)/(87.135)=0.01148Scm^(-1)`
`^^_(m)=(1000K)/(C)=(1000xx0.01148)/(0.05)=229.6Scm^(2)mol^(-1)`