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int(1)/(sin(x-a)cos(x-b))dx is equal to...

`int(1)/(sin(x-a)cos(x-b))dx` is equal to

A

`1/(cos(a-b))ln|(sin(x-a))/(cos(x-b))|+C`

B

`1/(cos(a-b))ln|(cos(x-a))/(sin(x-a))|+C`

C

`1/(sin(a-b))ln|(sin(x-a))/(cos(x-b))|+C`

D

`1/(sin(a+b))ln|(cos(x-a))/(sin(x-b))|+C`

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Knowledge Check

  • int 1/(sin(x-a)"sin"(x-b)) dx is equal to

    A
    `1/(sin(b-a)) log |("sin"(x+b))/(sin (x+a))|+C`
    B
    `1/(sin(b+a)) log |("sin"(x-b))/(sin (x-a))|+C`
    C
    `1/(sin(b-a)) log |("sin"(x-b))/(sin (x-a))|+C`
    D
    None of the above

  • int(1)/(sin^(2)x.cos^(2)x)dx is equal to

    A
    `sinx - cos x +C`
    B
    `tanx +cot x+C`
    C
    `cos x +sinx +C`
    D
    `tanx -cot x +C`

  • int(sin(x+a))/(cos(x-b))dx=

    A
    `x sin(a+b)+cos(a+b)log|sec(x-b)|+c`
    B
    `x sin(a-b)+cos(a-b)log|sec(x-b)|+c`
    C
    `x sin(a-b)-cos(a-b)log|sec(x-b)|+c`
    D
    `x sin(a+b)-cos(a+b)log|sec(x-b)|+c`

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