(a) In the arrangmenet shown in the figure the frictional coefficient between the traingular wedge and floor is `mu = 1//sqrt(3)`. The frictional force is sufficient to keep the system in equilibrium.
Find how much the normal reaction between the wedge and floor is displaced from the centre of mass of wedge. All other surface are frictionless. Assume masses of both the bodies same and equal to m. Radius of sphere =R, length of side of triangular wedge d `= 3 sqrt( 3) R `.

( b) If the surface of contact between the floor & the wedge also becomes frictionless, the find the speed of both bodies when sphere hits the ground. Initial height of centre of mass of sphere = 2R as shown.

Answer

(a) `x = 0 `, (b) `sqrt((3)/( 2) gR )`