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At 1090K, K(p) for the reaction CO(2)(...

At 1090K, `K_(p)` for the reaction
`CO_(2)(g) +C(s) rarr 2CO(g)` is 10 atm,
At the constant temperature ,Equilibrium position will shift, when pressure change occurs.
In the above reaction, at what total pressure will the gaes analyse 8% `CO_(2)` by volume ?

A

10 atm

B

0.23 atm

C

0.95 atm

D

0.45 atm

Text Solution

Verified by Experts

The correct Answer is:
C
Given`%` of `CO_(2) = 8, % CO = 92 `
`k_(p) = ((P_(CO))^(2))/((P_(CO_(2)))) = ( ( 0.92P)^(2))/( 0.08) = ( ( 0.92 )^(2) P )/(0.08) = 10`
`P = ( 10 xx 10.08)/( ( 0.92)^(2)) = 0.95 ` atm
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