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0.1 millie moles of CdSO(4) are present ...

`0.1` millie moles of `CdSO_(4)` are present in `10ml` acid solution of `0.08 N HCI`. Now `H_(2)S` si passed to precipitate all the `Cd^(2+)` ions. What would be the `pH` of solution after filtering off percipitate, boilling of `H_(2)S` and making the solution `100ml` by adding `H_(2)S`?

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