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The H-C-H bond angle in CH(4) is 109.5^(...

The H-C-H bond angle in `CH_(4) is 109.5^(@)`, due to lone pair repulsion, the H-O-H angle in `H_(2)O` will :

A

remain the same

B

increase

C

decrease

D

become `180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Assertion : H-S-H bond angle in H_(2)S is closer to 90^(@) but H-O-H bond angle in H_(2)O is 104.5^(@) Reason: lp-lp repulsion is stronger in H_(2)S than in H_(2)O