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An alpha-particle of mass 6.65xx10^-27kg...

An `alpha`-particle of mass `6.65xx10^-27kg` is travelling at right angles to a magnetic field with a speed of `6xx10^5ms^-1`. The strength of the magnetic field is `0.2T`. Calculate the force on the `alpha`-particle and its acceleration.

Text Solution

Verified by Experts

The correct Answer is:
(i) `3.84xx10^(-14)N`
(ii) `6xx10^(12)m//s^(2)`
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Knowledge Check

  • A proton enters a magnetic field with a velocity of 2.5 xx10^(7)ms^(-1) making an angle 30^(@) with the magnetic field. The force on the proton is (B=25T)

    A
    `1.25xx10^(-11)N`
    B
    `2.5xx10^(-11)N`
    C
    `5.0xx10^(-11)N`
    D
    `7.5xx10^(-11)N`

  • An electron and an alpha particle having equal velocities pass at right angles to the magnetic field.In this field

    A
    both the particles describe a circular path
    B
    both the particles move in straight path
    C
    the radius of the path of alpha particle is greater than that of electron
    D
    the velocity of electron becomes more than that of alpha particle

  • An electron and an alpha particle having equal velocities pass at right angles to the magnetic field.In this field

    A
    both the particles describe a circular path
    B
    both the particles move in straight path
    C
    the radius of the path of alpha particle is greater than that of electron
    D
    the velocity of electron becomes more than that of alpha particle