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If vecB(1),vecB(2) and vecB(3) are the m...

If `vecB_(1),vecB_(2)` and `vecB_(3)` are the magnetic field due to `l_(1),l_(2)` and `l_(3)`, then in Ampere's circuital law `ointvecB.vec(dl)=mu_(0)l, vecB` is

A

`vecB=vecB_(1)-vecB_(2)`

B

`vecB=vecB_(1)+vecB_(2)+vecB_(3)`

C

`vecB=vecB_(1)-vecB_(2)+vecB_(3)`

D

`vecB=vecB_(3)`

Text Solution

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The correct Answer is:
B
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