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If tan^-1(1/y)=-pi+cot^-1 y, where y=x^2...

If `tan^-1(1/y)=-pi+cot^-1 y,` where `y=x^2-3x+2,` then find the value of `x`

Text Solution

Verified by Experts

The correct Answer is:
`x in (1, 2)`
`tan^(-1) ((1)/(y)) = -pi + cot^(-1) y`
`rArr y lt 0`
`rArr x^(2) - 3x + 2 lt 0`
`rArr (x - 1) (x -2) lt 0`
`rArr x in (1, 2)`
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