एक रेडियोएक्टिव पदार्थ में समय `t_(1)` पर सक्रियता `R_(1)` तथा समय `t_(2)` पर सक्रियता `R_(2)` है | यदि पदार्थ का क्षय नियतांक `lambda` है, तब

Options

A. `R_(1) = R_(2) e^(-lambda (t_(1) - t_(2)))`
B. `R_(1) = R_(2) e^(lambda (t_(1) - t_(2)))`
C. `R_(1) = R_(2) (t_(2)//t_(1))`
D. `R_(1) = R_(2)`

Answer

A

Explanation

`because" "R_(1) = R_(0) e^(-lambda t_(1))`
`rArr" "R_(2) = R_(0) e^(-lambda t_(2))`
`rArr" " (R_(1))/(R_(2)) = (e^(-lambda t_(1)))/(e^(-lambda t_(2))) = e^(-lambda (t_(1) - t_(2)))`
`therefore" "R_(1) = R_(2) e^(-lambda (t_(1) - t_(2)))`