The angle between the pair of tangents drawn from a point `P` to the circle `x^2+y^2+4x-6y+9sin^2alpha+13cos^2alpha=0` is `2alpha` . then the equation of the locus of the point `P` is `x^2+y^2+4x-6y+4=0` `x^2+y^2+4x-6y-9=0` `x^2+y^2+4x-6y-4=0` `x^2+y^2+4x-6y+9=0`

Explanation

To solve the problem, we need to find the equation of the locus of the point \( P \) from which the angle between the pair of tangents drawn to the given circle is \( 2\alpha \).

### Step-by-Step Solution:

1. **Identify the Circle's Equation**:
The given equation of the circle is:
\[
x^2 + y^2 + 4x - 6y + 9\sin^2\alpha + 13\cos^2\alpha = 0
...