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Assign oxidation number to the underline...

Assign oxidation number to the underline elements in each of the following species:
`KAIunderline((S)O_(4))(2).12H_(2)O`

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Let the oxidation number S in KAI`(SO_(4))_(2).12H_(2)O`be x `therefore underset(("For K"))(1(+1))+underset(("For all"))(1(+3))+2x+underset(("For O"))(8(-2))+12underset(("For"H_(2)O))([2xx1-2])=0`
`therefore` x=+6
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CHHAYA PUBLICATION-REDOX REACTIONS -SOLVED NCERT EXERCISE
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