Calculate the oxidation number of sulphur, chromium and nitrogen in `H_(2)SO_(5),Cr_(2)O_(7)^(2-)&NO_(3)^(-)`,Suggest structure of these compounds .

Explanation

`H_(2)SO_(5)`
`Cr_(2)O_(7)^(2-)`: If the oxidation number of Cr in `Cr_(2)O_(7)^(2-)` be x `then 2(x)+underset(("for O"))(7(-2))=-2 therefore x=+6`
The strucutre `Cr_(2)O_(7)^(2)`
Therefore ,there in no fallacy
`NO_(3)^(-)` According to conventional method , the oxidation number of N in `NO_(3)^(-)`: x+3(-2)=-1 or, x= +5 (where x= oxidation number of N in `NO_(3)^(-)`
However according to chemical bonding method , the structure of `NO_(3)^(-))`
However according to chemical bonding method the structure of `NO_(3)^(-)` is : if the oxidation numbber o fN in the the above structure be x, `then, underset(("for"O^(-)))(x+(-1))underset(("for=O"))(+(-2)+)underset(("for"toO))((-2)=0)`
or, x=+5
So in both conventional and chemical bonding methods ,the oxidaiton number of N in `NO_(3)^(-)` is +5 .
Therefore ,there is no fallacy.