Balance the following redox reactions by ion -electron method:
`H_(2)O_(2)(aq)+Fe^(2+)(aq) to Fe^(3+)(aq)+H_(2)O(l)`(in acidic solution)

Explanation

Oxidation reaction : `Fe^(2+)(aq)toF^(3+)(aq)+e`
Reduction reaction: `H_(2)O_(2)(aq)+2H^(+)_(2)O(l)`
Multipying equation (1) and (2) then adding it to equation (2), we have
`2Fe^(2+)(aq)+H_(2)O_(2)(aq)+2H^(+)(aq)2Fe^(3+)(aq)+2H_(2)O(l)`