Home
Class 12
PHYSICS
The refracting angle of a prism is A, an...

The refracting angle of a prism is A, and refractive index of the material of the prism is cot `(A // 2)`. The angle of minimum deviation is

A

`180^(@) - 3A`

B

`180^(@) - 2A`

C

`90^(@) - A`

D

`180^(@) + 2A`

Text Solution

Verified by Experts

The correct Answer is:
B

`"We know" , mu = sin""(A + delta_(m))/(sin""(A)/(2))`
`or, sin""(A + delta_(m))/(2) = mu sin""(A)/(2) = cot""(A)/(2) sin""(A)/(2)`
`= cos""(A)/(2) = sin(90^(@) - (A)/(2))`
`therefore (A + delta_(m))/(2) = 90^(@) - (A)/(2)`
`or, " " A + delta_(m) = 180^(@) - A or, delta_(m) = 180^(@) - 2A`
Promotional Banner

Topper's Solved these Questions

  • REFRACTION OF LIGHT

    CHHAYA PUBLICATION|Exercise NEET|3 Videos
  • REFRACTION OF LIGHT

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|11 Videos
  • REFRACTION OF LIGHT

    CHHAYA PUBLICATION|Exercise JEE MAIN|2 Videos
  • REFLECTION OF LIGHT

    CHHAYA PUBLICATION|Exercise INTEGER ANSWER TYPE|3 Videos
  • SEMICONDUCTORS AND ELECTRONICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|31 Videos

Similar Questions

Explore conceptually related problems

The relation between angle of the prism and refractive index of the medium is:

Refractive index of the material of an equilateral prism is sqrt(2) .

The angle of prism is A and refractive index is cot A/2 . The minimum deviation of the prism—

The refracting angle of a prism is 60^(@) and the refractive index of its material is sqrt((7)/(3)). Find the minimum angle of incidence of a ray of light falling on one refracting face of the prism such that the emerging ray will graze the other refracting face.

A monochromatic ray of light in incident normally on a refracting face of a prism of angle 30^(@) . The refractive index of the material of the prism 1.5 . The angle of emergence will be

If the refracting angle of a prism is A, the refractive index of its material is mu and the angle of deviation of a ray of light incident normally on the first refraction face is delta , then prove that mu = sin(A + delta)/(sinA).

A monochromatic ray of light is incident normally on a refracting face of a prism of angle 30^(@) . If the refractive index of the material of the prism is 1.5 , calculate the angle of emergence and the angle of deviation. [sin48.6^(@) = 0.75]

The refracting angle of a glass prism is 60^(@) and the refractive index of glass is 1.6. If the angle of incidence of a ray of light on the first refracting surface is 45^(@) Calculate the angle of deviation of the ray . Given that sin 26^(@)14' = 0.4419, " " sin33^(@)46' = 0.5558 and sin62^(@)47' = 0.8893

The refracting angle of a prism is 60^(@) and its refractive index is sqrt((7)/(3) . What should be the minimum angle of incidence on the first refracting surface so that the ray can emerge somehow from the second refracting surface?