The expression for the velocity of a particle at time t is `v = at+ (b)/(t+c)` , where the units of v and t are m.`s^(-1)` and s, respectively. What are the dimensions of a,b and c?

The velocity of a particle in time t is v = at + (b)/(t+c) . The dimension of a, b and c are

The velocity V of a particle at time t is given by V = at + b/(t+c) . The dimensions of a, b and c are respectively--------.

The velocity of a particle (v) at an instant 't' is given by v = at + bt^(2) , the dimension of b is

If x = a+bt+ ct^(2) , where x is in metres and t in seconds what are the dimensions of b and c?

The instantaneous position of a particle is given by S(t) = V_(0) (1 - e^(-at))//a , where a and V_(0) are constants and a gt 0 . What are the dimensions of a and V_(0) ?

The velocity v of a particle is related to time t as v = 4+2 (c_(1)+c_(2)t) , where c_(1) and c_(2) are constants . Find out the initial velocity and acceleration.

The initial velocity of a particle- is u and acceleration (f) is uniform. Final velocity and distance covered in the interval t are v and s respectively. Show that the velocity of the particle at half - distance is more than the velocity for half-time.

The velocity of a particle moving in a straight path is given by v=16t-4t^(2) where v and t measured in ft/s and second units respectively. If the initial displacement be 10 ft, find the displacement of the particle in t seconds.

If F = at^-1 + bt^2 be any equation where F = force, t = time, a and b arc cosntant. Then what is the dimension of a and b?

The velocity of a moving particle is given by v = 6 +18t + 9t^(2) (x in metre t in second ) what is its acceleration at t = 2 s?