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The dimension of universal constant of g...

The dimension of universal constant of gravitation G is

A

`ML^(2)T^(-1)`

B

`M^(-1)L^(3)T^(-2)`

C

`M^(-1)L^(2)T^(-2)`

D

`ML^(3)T^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`[G] = [(Fr^(2))/(m_(1)m_(2))]` [from Newton.s law of gravitation]
`=(MLT^(-2)xxL^(2))/(M^(2))=M^(-1)L^(3)T^(-2)`
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