Home
Class 11
PHYSICS
Given veca+vecb+vecc+vecd=vec0. Show th...

Given `veca+vecb+vecc+vecd=vec0`. Show that : the magnitude of `(veca+vecc)` equals the magnitude of `(vecb+vecd)`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
Promotional Banner

Topper's Solved these Questions

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Comprehension type)|10 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Integer answer type)|2 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Assertion -reason type)|12 Videos

  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|9 Videos

Similar Questions

Explore conceptually related problems

If (vecA+vecB)*(vecA-vecB)=0 , show that the magnitude of both the vectors are equal .

If veca xx vecb + vecb xx vecc + vecc xx veca = 0 . Show that the vectors veca, vecb, vecc are coplanar.

If [ veca vecbvecc]=2 , then find the value of [(veca+2vecb-vecc) (veca - vecb) (veca - vecb-vecc)]

Let veca, vecb, vecc be three unit vectors and veca.vecb=veca.vecc=0 . If the angle between vecb and vecc is pi/3 then find the value of |[veca vecb vecc]|

For any two vectors vecA and vecB, if vecA*vecB=|vecAxxvecB| , the magnitude of vecC=vecA+vecB is equal to

If veca+vecb=vecc , and a+b=c then the angle between veca and vecb is

If veca, vecb, vecc and vecd are distinct vectors such that veca xx vecc = vecb xx vecd and veca xx vecb = vecc xx vecd . Prove that (veca-vecd).(vecb-vecc)ne 0

If veca,vecb and vecc are three mutually perpendicular vectors of equal magnitude, show that vec a + vecb + vecc is equally inclined to veca, vecb and vecc . Also find the angle.