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vecA bot vecB,vecC is coplanar with vecA...

`vecA bot vecB,vecC` is coplanar with `vecA and vecB`. Therefore,

A

`vecA=xvecB+yvecC`, where x and y are scalars

B

`vecA*(vecBxxvecC)=0`

C

`|(vecAxxvecB)xxvecC|=ABC`

D

`vecA*vecB=0`

Text Solution

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The correct Answer is:
A, B, C, D
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