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If vecA*vecB=|vecAxxvecB| then the angle...

If `vecA*vecB=|vecAxxvecB|` then the angle between `vecA and vecB` is

A

`pi`

B

`(pi)/2`

C

0

D

`(pi)/4`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecA*vecB=|vecAxxvecB|`
or, `AB cos theta =AB sin theta or, tan theta =1`
`therefore theta=(pi)/4`
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