What amount of concentrated sulphuric acid (specific gravity 1.8) should be mixed with 1 L of water so that specific gravity of the mixture becomes 1.24?
Text Solution
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Let the required volume be `vcm^(3)`. Mass of that volume of acid = 1.8 vg and mass of 1 L of water = 1000g `therefore" "` Total mass = (1.8v + 1000)g and total volume `(v+1000)cm^(3)` `therefore` Specific gravity of the mixture = `(1.8v+1000)/(v+1000)` `therefore" "(1.8v+1000)/(v+1000)=1.24` or, (1.8 - 1.24)v = 1240 - 1000 or, 0.56v = 240 or, `v=428.6cm^(3)`.
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