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The lockgate of a canal is 4.8 m broad. ...

The lockgate of a canal is 4.8 m broad. The depth of water on one side of the lockgate is 4.5 m and on the other side is 3m. Calculate the total thrust on the lockgate. The density of water = `1000kg*m^(-3)`.

Text Solution

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Thrust exerted by the water column of depth 4.5 m on one side of the lockgate
`=1/2xx4.5xx1000xx(4.5xx4.8)xxg=48600kgxxg`
Thrust exerted by the water column of depth 3 m on the other side of the lockgate
`=1/2xx3xx1000xx(3xx4.8)xxg=21600kgxxg`
Since, these two thrusts are mutually opposite in direction, the net thrust on the lockgate
= `(48600-21600)xxg=2.65xx10^(5)N`.
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