At what depth below the surface of a lake will the total pressure be twice the atmospheric pressure? (Atmospheric pressure = 76 cm Hg and the density of mercury = 13.6`g*cm^(-3)`)
Text Solution
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If the required depth is h and the atmospheric pressure is p, then `2p=p+hrhog` or, `p=hrhogor,76xx13.6xxg=hxx1xxg` `therefore" "h=76xx13.6=1033.6cm`.
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