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A U-tube is partially filled with mercur...

A U-tube is partially filled with mercury. Kerosene oil is poured into one of its limbs and glycerine into the other. It is observed that, when the height of the kerosene oil becomes 20 cm and that of glycerine becomes 12.68 cm, the levels of the mercury column in the two limbs are at the same horizontal level. If the density of kerosene oil is `0.8g*cm^(-3)`, then find that of glycerine.

Text Solution

Verified by Experts

In the U-tube mercury levels in the two limbs are at same horizontal level.

So, pressure exerted by 20 cm of kerosene oil = pressure exerted by 12.68 cm of glycerine. Let the density of glycerine be `rho`.
`therefore" "20xx0.8xxg=12.68xxrhoxxg`
or, `rho=(20xx0.8)/(12.68)=1.26g*cm^(-3)`.
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