A body weighs `100gxxgand40gxxg` in air and water respectively. Calculate the weight of the body when immersed in a liquid of specific gravity 0.8.
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Weight of the body in air = `100xxg`, weight of the body in water = `40gxxg`. `therefore` Weight of displaced water = `(100-40)xxg=60gxxg`. `therefore` Volume of displaced water = `60cm^(3)` So, the volume of the body = `60cm^(3)` Specific gravity of the liquid = 0.8 `therefore` Density of the liquid = `0.8g*cm^(-3)`. `therefore` Weight of the displaced liquid `=(60xx0.8)xxg=48gxxg`. `therefore` Weight of the body in the liquid = Weight of the bodyin air - weight of the displaced liquid = `(100-48)xxg=52gxxg=50960dyn`.
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