The weight of a body in air is `0.4gxxg`. Its weight along with an sinker in water = `3.37gxxg`. The weight of the sinker in air = `4gxxg`. Find the specific gravity of the body. [Specific gravity of the sinker = 8]
Text Solution
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Let the density of the body be `dg*cm^(-3)`. `therefore` Volume of the body = `0.4/dcm^(3)`, volume of the sinker = `4/8=0.5cm^(3)` `therefore` Volume of water displaced by the body along with the sinker = `(0.5+0.4/d)cm^(3)` `therefore` Weight of displaced water = `(0.5+0.4/d)gxxg` Again, weight of displaced water = weight of the body along with sinker in air - weight of the body along with sinker in water `=(0.4+4)xxg-3.37xxg=(4.4-3.37)xxg` `=1.03gxxg` `therefore" "0.5+0.4/d=1.03or,0.4/d=0.53` or, `d=0.4/0.53=0.75` `therefore` Specific gravity of the body = 0.75.
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