There is a cavity inside a piece of metal of mass 237.3g. The apparent weight of the piece of metal immersed completely in water is `192.1gxxg`. If the density of the metal is `7.91g*cm^(-3)`, then find the volume of the cavity.
Text Solution
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Volume of the material of the metal piece = `(237.3)/(7.91)=30cm^(3)`, mass of water displaced by the metal piece `=(237.3-192.1)xxg=45.2gxxg` `therefore` Volume of displaced water = `45.2cm^(3)` `therefore` Volume of the cavity = 45.2 - 30 = 15.2cm^(3)`.
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